Question

Plz help me

Answer 1

6.6 g

Explanation:

The mole ration between CaCO₃and CO₂ is 1 : 1

Because the molar mass of CaCO₃ is 100.0869 g/mol the amount of moles used in this chemical reaction is;

15/ 100

This will be similar to the moles of CO₂

Because the molar mass of CO₂ is 44g, then well multiply by the moles;

15/100 * 44

= 6.6 g