Answer:
B.) Magma
Explanation:
Lava - Magma that reaches Earth's through a volcanic vent
Magma - Composed of molten mixture of rock-forming substances, gases and water
Batholith - Very large igneous intrusion extending deep in the earth's crust
Slurry - Semiliquid mixture, typically of fine particles of manure, cement, or coal suspended in water
Answer:
T₂ = 859.4 K
Explanation:
Given data:
Initial volume of gas = 32.0 L
Initial temperature = 2°C (2 + 273 = 275 k)
Final temperature = ?
Final volume = 1.00 ×10²L
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 1.00 ×10²L × 275 K / 32.0 L
T₂ = 27500 L.K / 32.0 L
T₂ = 859.4 K
Alkali Metals have 2 valence electrons
Answer:
option D = N₂ + 3H₂ → 2NH₃
Explanation:
The reaction in which the nitrogen and hydrogen are reacted to form the ammonia is true.
N₂ + 3H₂ → 2NH₃
In this reaction we can see that one molecules of nitrogen react with three molecules of hydrogen and form two molecules of ammonia.
while the other options are in correct because,
2SO₂ + O₂ → 2SO₃
In this reaction two molecules of SO₂ react with one molecule of oxygen and form two molecules of SO₃.
2H₂S + 3O₂ → 2SO₂ + 2H₂O
In this reaction two molecules of H₂S react with three molecules of oxygen and produced four molecules of product.
SnO₂ + 2H₂ → Sn + 2H₂O
This is also incorrect because three molecules of reactant form three molecules of product.
Answer:
The pH of the solution is 9.43
Explanation:
sodium acetate = CH3COONa
after removing the spectator ion Na
CH3COO⁻ + H2O ⇄ CH3COOH + H3O⁺
since sodium acetate is a weak base, it will not react completely with water. Thus a value "x" will be used to make the products.
At equilibrium:
[CH3COO⁻] = 1.288 - x
[CH3COOH] = x
[H3O⁺] = x
Since a base is reacting with H2O, Kb is used at equilibrium: Kb=(1*10^-14)/(1.8*10^-5) = 5.6*10^-10)
Kb = [CH3COOH][H3O⁺]/[CH3COO⁻]
Kb = (x²)/(1.288-x) since the Kb is significantly lower than 1.288 we can make a mathematical assumption that x is significantly lower than 1.288.
5.6*10⁻¹⁰ = x²/1.288
x = [OH⁻] = 2.675*10⁻⁵ M
pOH = -log[OH⁻] = 4.57
pH=14-pOH = 14 - 4.57 = 9.43
