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sdas [7]
3 years ago
6

A circle is shown. Secants R S and R T intersect at point R outside of the circle. Secant R S intersects the circle at point U.

Secant R T intersects the circle at point V. The length of R U is 6, the length of U S is 10, and the length of R V is 8.
If secant segments SR and TR intersect at point R, find the length of VT.

Start by relating the secants and segments theorem to this diagram:

(RS)() = ()(RV)

Substitute values from the diagram into the equation:

(16)() = ()(8)

Solve for VT:

VT =
Mathematics
2 answers:
allsm [11]3 years ago
7 0

Answer:

Everything in -> [x]

(RS) [(RU)] = [(RT)] (RV)

(16) [(6)] = [(8+VT)] (8)

VT = [4]

Step-by-step explanation:

I just did the assignment, you're welcome.

Leno4ka [110]3 years ago
7 0

Answer:

(RS) [(RU)] = [(RT)] (RV)

(16) [(6)] = [(8+VT)] (8)

VT = [4]

Step-by-step explanation:

Here mi amor

jk

Lol

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2x+y=3 passes from origin. is this statement true or false
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Answer:

the answer is false.

Step-by-step explanation:


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Probability of pulling a green marble out of a bag of coloured marble is 2:5 if you were to pull coloured marbles out of the bag
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Determine the discriminant of x2 = 4. <br><br> A. 17 <br> B. 16 <br> C. -15 <br> D. -10
tino4ka555 [31]
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6 0
3 years ago
Read 2 more answers
I need help on 17 and 23 pls
ludmilkaskok [199]

                           

                          Question # 17 Solution

Answer:

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Step-by-step Explanation:

The given expression

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

And we have to solve for x₁

So,

Lets solve for x₁.

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Multiply both sides by x₂ - x₁

m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m(x_{2}-x_{1})= (y_{2}-y_{1})

mx_{2}-mx_{1}= (y_{2}-y_{1})

-mx_{1}= y_{2}-y_{1}-mx_{2}

Divide both sides by -m

\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Therefore, x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

                                     Question # 23 Solution

Answer:

n= \frac{bx}{-b + x}

Step-by-step Explanation:

The given expression

\frac{nx}{b}-x=x

And we have to solve for n

So,

Let's solve for n.

\frac{nx}{b}-x=x

Multiply both sides by b.

-bn + nx = bx

Factor out n.

n(-b + x)= bx

Divide both sides by -b + x.

\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}

n= \frac{bx}{-b + x}

Therefore, n= \frac{bx}{-b + x}

<em>Keywords: solution, equation</em>

<em>Learn more about the solution of equations from brainly.com/question/12864981</em>

<em>#learnwithBrainly</em>

6 0
3 years ago
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