Answer:
Step-by-step explanation:
We would apply the simple interest formula which is expressed as
I = PRT/100
Where
P = principal or amount borrowed
T = time in years
R = interest rate on amount borrowed.
I = interest paid.
From the given information,
Principal = $3000
T = 3 months = 3/12 = 0.25 years
R = 6 1/2 % = 6.5%
Therefore,
a) the amount that the woman pay for the use of the money is I
I = (3000 × 6.5 × 0.25)/100 = 48.75
b) The amount she repaid to the bank on the due date of the note would be
Principal + interest
= 3000 + 48.75 = $3048.75
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
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The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
Answer:
141 cans per day
Step-by-step explanation:
2000 goal cans - 872 collected cans = 1,128 still needed
1,128/8 days = 141 cans per day
I don’t get this question
I think its because log e is ln so ln is a natural logarithm.
