If you take the square root of a number squared number then they cancel each other out and the number stays the same i.e. √[(4)^2] would equal 4.
In this problem the square root and numbered squared cancel out to leave the problem as -2a.
The solution of this problem is -2a
k = 13The smallest zero or root is x = -10
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Steps:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+1 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Please mark brainliest
<em><u>Hope this helps.</u></em>
18=3(x-1)
18=3x-3
18-3=3x
15=3x
15/3=x
x=5
Answer:
8100/8100
I think this the answer to your question.
Step-by-step explanation: