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snow_tiger [21]
3 years ago
8

What is the difference between the mean and the median of the following distribution?

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
First you find the median which is 4. The mean is calculated by the sum of the distribution divided by the amount of numbers in the distribution (20). The mean comes out to be 4.35. Subtract 4.35 from 4 and your answer is .35.
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GOOD AT GEOMETRY??? NEED BRAINLIEST AND POINTS?? YOU NEED MY HELP AND I NEED YOURS! ALL YOUR HELP IS APPRECIATED!!!
jeyben [28]

Answer:

<h2>In a quadrilateral, opposite angles are congruent.</h2>

Step-by-step explanation:

Angle B & D are both opposite to each other, yet congruent.

8 0
3 years ago
(ab² + 13b - 4a) + (3ab² + a +7b)
Natalija [7]

Answer:

4ab² + 20b - 3a

Step-by-step explanation:

This question most likely asks us to simplify the expression, as factoring is not possible...

(ab² + 13b - 4a) + (3ab² + a + 7b),

ab² + 13b - 4a + 3ab² + a + 7b,

ab² + 3ab² + 13b + 7b - 4a + a,

Solution : 4ab² + 20b - 3a

4 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
The area of the shaded circle below is 78.5 square inches. The area of the large circle is 314 square inches.
umka2103 [35]
From the given description it seems that the small shaded circle lies within the larger circle as shown in image below:

The probability that a point choosen at random lies within the shaded area = Area of shaded region / Total area of the bigger cricle

So,
Probability = 78.5/314 = 0.25

Thus there is 0.25 or 25% probability that the point chosen at random will lie inside the shaded region. 

6 0
3 years ago
Read 2 more answers
Which of the following diagrams represents 80%?<br><br>Help please. it'd be very appreciated. :)​
Alenkasestr [34]

Answer:

H

Step-by-step explanation:

there is 10 parts to the shape so your denominator would be 10 then if you count the shaded area there's 8, so 8 would be your numerator

8/10 = 0.8 or 80%

5 0
3 years ago
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