289 square root = 17
17*17=289
Say 17 was length and 17 was width. L*w=289
Also, all sides of the square are the same.
Answer:
Step-by-step explanation:
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
Answer:
D
The line shows an intercept of -3 and a slope of 5/7. Equation D displays this
Step-by-step explanation:
Answer:
the volume of the larger cube is 512
Step-by-step explanation:
we plug in the value of the side into the equation
so we get
8 x 8 x 8= 512
hope this helps <3
