B: 6.03 The more numbers to the right of the decimal the more precise and accurate the number will be
Complete the square fr x and y's sepreatly to get into form
(x-h)²+(y-k)²=r²
the center is (h,k) and radius is r
so
group x's and y's seperatly
(4x²-10x)+(4y²+24y)+133/4=0
undistribute leading confident from each
4(x²-2.5x)+4(y²+6y)+133/4=0
take 1/2 of each linear confident and square it and add negative and positive inside the parenthasees
-2.5/2=-1.25 (-1.25)²=1.5625
6/2=3, 3²=9
4(x²-2.5x+1.5625-1.5625)+4(y²+6y+9-9)+133/4=0
factor perfect squares
4((x-1.25)²-1.5625)+4((y+3)²-9)+133/4=0
expand
4(x-1.25)²-6.25+4(y+3)²-36+133/4=0
4(x-1.25)²+4(y+3)²-9=0
add 9 to both sides
4(x-1.25)²+4(y+3)²=9
divide both sides by 4
(x-1.25)²+(y+3)²=9/4
(x-1.25)²+(y+3)²=(3/2)²
the center is (1.25,-3) and the radius is 1.5
Answer:
y=2/3×+6
Step-by-step explanation:
y-2=2/3(×+6)
y=2/3x4+2
y=2/3×+6
You can subtract 4 from 13 then subtract 4 again
Answer - D.
you basically find the equation of the line first and eliminate the wrong answers...
Strategy: before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,
First you have to find the gradient (m) of the line.
you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2
replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others
Hope you get it!