All categories

3 years ago

What function is graphed below?

Mathematics

2 answers:

STatiana [176]3 years ago

8 0

Answer:

option (A) y = $2x^{4}$

Step-by-step explanation:

Since the given graph represents a parabola passing through origin so equation of the parabola will be

Either y = $2x^{4}$ or y = $-2x^{4}$

y = 2x³ or y = -2x³ not a graph a parabola

Now we know if coefficient of $x^{4}$ is positive then opening of the parabola is upwards end opening is downwards is coefficient of $x^{4}$ is negative.

Therefore, for the given graph option (A) y = $2x^{4}$ is the answer.

allochka39001 [22]3 years ago

5 0

It's the first one ....

You might be interested in

Next Ron has to add 2.1 grams of medication to 3.4 grams of another medication. What is the total amount of medication he needs

Brums [2.3K]

Answer:

He needs to take 5.5 grams of medications.

Step-by-step explanation:

I added 2.1 to 3.4 and got 5.5. *booyah*

4 0

3 years ago

Find the Y INTERCEPT and SLOPE of the line <br> 5x+3y= -4<br> Y INTERCEPT= <br> SLOPE=

Veronika [31]

Rearrange the equation so the left side starts out as y =

5x + 3y = -4
3y = -5x - 4
y = (-5/3)x - (4/3)

the slope is in front of the x and the y-intercept iis the other number
slope is -5/3
y-interxept = -4/3

6 0

3 years ago

Which relation represents a function? StartSet (0, 0), (2, 3), (2, 5), (6, 6) EndSet StartSet (3, 5), (8, 4), (10, 11), (10, 6)

postnew [5]

Answer:

<h2>Third set.</h2>

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A function is defined as a relation where each x-value (domain), has only one y-vale assigned (range). If one x-value has more than one image in the range, therefore, that's not a function. So, let's see which relation represents a function.

First: (0, 0), (2, 3), (2, 5), (6, 6).

As you can see, this set doesn't represent a function, because for x=2 there are two images assigned y=3 and y=5.

Second: (3, 5), (8, 4), (10, 11), (10, 6).

Similarly, this relation is not a function, because x=10 has to images, y=11 and y=6.

Third: (-2, 2), (0, 2), (7, 2), (11, 2)

As you can see, this is a function, because each pair has different value in the domain. Notice that there's the same image for each x-value, that still fulfil the definition of a function, because one element in the image can have multiple elements in the domain, what cannot happen is the opposite case.

Fourth: (13, 2), (13, 3), (13, 4), (13, 5).

This relation is not a function, because the same x-value has multiple images.

Therefore, the right answer is the third set.

8 0

3 years ago

Read 2 more answers

Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.

ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is $-9 x \times x \times x \times(x-7) \times(x+3)$