Help with this plz on finding x

Mathematics

1 answer:

ratelena [41]4 years ago

3 0

M<3 = m<5
10x = 12x - 25
2x = 25
x = 12.5

answer is A. first choice

You might be interested in

Please help!!

morpeh [17]

find from goggle please

6 0

3 years ago

Five number have amean of 12,when one number is removed, the mean becomes 11,what is the removed number

Ugo [173]

Answer:

The removed number is 16

Step-by-step explanation:

Five numbers have a mean of 12.

Now;

Mean = Σx/x

Thus; Σx = 12 × 5 = 60

Now,we are told that if one number is removed, the mean is 11.

Thus;

(60 - x)/4 = 11

60 - x = (11 × 4)

60 - x = 44

x = 60 - 44

x = 16

Thus,the removed number is 16

5 0

3 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$