Answer:
If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18
If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46
Step-by-step explanation:
We are given the following data-set:
70, 65, 71, 78, 89, 68, 50, 75
Deviations from the mean
–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2
Sample size, n = 8
Sample:
where
are data points,
is the mean and n is the number of observations.
Sum of squares of differences =
0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5
![s = \sqrt{\dfrac{875.5}{7}} = 11.18](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cdfrac%7B875.5%7D%7B7%7D%7D%20%3D%2011.18)
![\text{ Sample variance} = s^2 = 125.07](https://tex.z-dn.net/?f=%5Ctext%7B%20Sample%20variance%7D%20%3D%20s%5E2%20%3D%20125.07)
Population:
where
are data points,
is the mean and n is the number of observations.
Sum of squares of differences =
0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5
![\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cdfrac%7B875.5%7D%7B8%7D%7D%20%3D%2010.46)
![\text{ Population variance} = \sigma^2 = 109.44](https://tex.z-dn.net/?f=%5Ctext%7B%20Population%20variance%7D%20%3D%20%5Csigma%5E2%20%3D%20109.44)