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ikadub [295]
3 years ago
11

What is the inverse of "f"if f(x)=^3 sqrtx-5

Mathematics
2 answers:
sashaice [31]3 years ago
8 0
<span>y=<span><span>x−5</span><span>−−−−</span>√3

</span></span> <span><span>x=<span><span>y−5</span><span>−−−−</span>√3
 </span></span></span>
Cloud [144]3 years ago
5 0
Assuming that the original equation is
f(x)= \sqrt[3]{x-5}

the inverse of f(x) is f(y)

f(x)= \sqrt[3]{x-5}
   y=\sqrt[3]{x-5}

f₋₁(y)= \sqrt[3]{y-5}
   x=\sqrt[3]{y-5}
   x³= y-5
   y=x³+5

Thus f₋₁=y=x³+5
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2 years ago
34 less than the product of 14 and an unknown number is 78
Lubov Fominskaja [6]
34 less than (-34) the product of (multiply) 14 (14) and an unknown (x) is (=) 78 (78)

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6 0
2 years ago
Read 2 more answers
What type of number is -2i?
Iteru [2.4K]

Answer:

It is an imaginary number.

Step-by-step explanation:

In this example, the real number is -2 is being multiplied by the imaginary unit, i, which i can be also expressed as (√-1).

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I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

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Step-by-step explanation:

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