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ikadub [295]
4 years ago
11

What is the inverse of "f"if f(x)=^3 sqrtx-5

Mathematics
2 answers:
sashaice [31]4 years ago
8 0
<span>y=<span><span>x−5</span><span>−−−−</span>√3

</span></span> <span><span>x=<span><span>y−5</span><span>−−−−</span>√3
 </span></span></span>
Cloud [144]4 years ago
5 0
Assuming that the original equation is
f(x)= \sqrt[3]{x-5}

the inverse of f(x) is f(y)

f(x)= \sqrt[3]{x-5}
   y=\sqrt[3]{x-5}

f₋₁(y)= \sqrt[3]{y-5}
   x=\sqrt[3]{y-5}
   x³= y-5
   y=x³+5

Thus f₋₁=y=x³+5
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Step-by-step explanation:

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3 years ago
Point N is on line segment MO. Given NO=2x−3, MO=3x+5, and MN=2x+3, determine the numerical length of MO.
ELEN [110]

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Step-by-step explanation:

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How many $10$-digit numbers are there, such that the sum of the digits is divisible by $2$?
navik [9.2K]

Complete question is;

How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?

Answer:

There are 4500000000 ten digit numbers whose sum is divisible by 2.

Step-by-step explanation:

Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.

While the last 10 digit number whose sum is divisible by 2 is 9999999999.

Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;

((9999999999 - 1000000001)/2) + 1 = 4500000000

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natta225 [31]
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