What is the inverse of "f"if f(x)=^3 sqrtx-5
2 answers:
<span>y=<span><span>x−5</span><span>−−−−</span>√3
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<span><span>x=<span><span>y−5</span><span>−−−−</span>√3
</span></span></span>
Assuming that the original equation is
f(x)=
![\sqrt[3]{x-5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx-5%7D%20)
the inverse of f(x) is f(y)
f(x)=
![\sqrt[3]{x-5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx-5%7D%20)
y=
![\sqrt[3]{x-5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx-5%7D%20)
f₋₁(y)=
![\sqrt[3]{y-5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By-5%7D%20)
x=
![\sqrt[3]{y-5}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By-5%7D%20)
x³= y-5
y=x³+5
Thus f₋₁=y=x³+5
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