The calculations are incorrect because the angles in a parallelogram are either:
The same
or complimentary (add up to 180)
Neither case is true here so the calculations are incorrect.
Answer: A and D
Step-by-step explanation:
Dependent events mean that one event depends on the outcome of the previous event.
A) If the first roll is a 3, and we want to sum more than 7 with the second roll, then the possible outcomes 5 and 6. Now if the first roll is 4, then the possible outcomes for the second event will be 4, 5 and 6. So you can see how the outcome space of the second event changes depending on the first event, so the events are dependent.
B) Here we do not have dependence, each event only depends on it's own outcome.
C) Again, both events only depend on it's own outcome, so the events are not dependent.
D) This is similar as the case for A, these events are dependent because is not the same if the outcome of the first event is 3, than if the outcome is 5 (the outcome needed for the second roll changes depending on the outcome of the first event)
E) Same as B and C, the events are independent.
Answer: You will pay $13.52 for this shirt.
Step-by-step explanation: 0.9435
Since the tax is 7.5%, you have to multiply 12.58 by 7.5% to find the amount of money paid as tax.
7.5% = 0.075
12.58 x 0.075 = 0.9435
Since we are dealing with money we have to round to the nearest hundredth -- 0.9435 = 0.94
Then to find the final cost of the shirt, we have to add 12.58 and 0.94 to get $13.52.
Answer:
The initial population was 2810
The bacterial population after 5 hours will be 92335548
Step-by-step explanation:
The bacterial population growth formula is:

where P is the population after time t,
is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours
Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:





Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:



Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:


= 39.84
:
100^2=251
10000=251
ℎ
251 ℎ
10000/251=251/251
39.84=1
39.84=