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ivanzaharov [21]
3 years ago
12

What is one possible interpretation of the section of the graph from point c to point d

Mathematics
1 answer:
Alina [70]3 years ago
7 0
Do you have an image?
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4C2 + 6C + 3C2 - 2C - 3
Gnesinka [82]
<span><span> 4c2+6c-3c2-2c-3</span> </span>

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "c2"   was replaced by   "c^2".  1 more similar replacement(s).

Step by step solution :<span>Step  1  :
</span><span>Equation at the end of step  1  :</span><span><span> ((((4•(c2))+6c)-3c2)-2c)-3 </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> (((22c2 + 6c) - 3c2) - 2c) - 3 </span><span>Step  3  :</span>Trying to factor by splitting the middle term

<span> 3.1 </span>    Factoring <span> c2+4c-3</span> 

The first term is, <span> <span>c2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +4c </span> its coefficient is <span> 4 </span>.
The last term, "the constant", is <span> -3 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -3 = -3</span> 

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is  <span> 4 </span>.

<span><span>     -3   +   1   =   -2</span><span>     -1   +   3   =   2
</span></span>Final result :<span> c2 + 4c - 3 </span>
3 0
3 years ago
720 pt/h=______ qt/min
Gennadij [26K]
1 pt = 0.5 qts.....so 720 pts = (720 * 0.5) = 360 qts
1 hr = 60 minutes

360/60 = 6

720 pt/hr = 6 qts/min
7 0
3 years ago
In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0
3 years ago
I need help lol last one
Andrei [34K]

Answer:

x= 19

If you need help with more, I'm more than happy to help you.

6 0
3 years ago
Read 2 more answers
Find an irrational number that is between 5.2 and 5.5
uysha [10]

Answer:

answer is 5.3 cuz I am smart I learned this so I'm here to help

6 0
3 years ago
Read 2 more answers
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