<span><span> 4c2+6c-3c2-2c-3</span> </span>
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "c2" was replaced by "c^2". 1 more similar replacement(s).
Step by step solution :<span>Step 1 :
</span><span>Equation at the end of step 1 :</span><span><span> ((((4•(c2))+6c)-3c2)-2c)-3
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span> (((22c2 + 6c) - 3c2) - 2c) - 3
</span><span>Step 3 :</span>Trying to factor by splitting the middle term
<span> 3.1 </span> Factoring <span> c2+4c-3</span>
The first term is, <span> <span>c2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> +4c </span> its coefficient is <span> 4 </span>.
The last term, "the constant", is <span> -3 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -3 = -3</span>
Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is <span> 4 </span>.
<span><span> -3 + 1 = -2</span><span> -1 + 3 = 2
</span></span>Final result :<span> c2 + 4c - 3 </span>
1 pt = 0.5 qts.....so 720 pts = (720 * 0.5) = 360 qts
1 hr = 60 minutes
360/60 = 6
720 pt/hr = 6 qts/min
Answer:
The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
427 had paid for coaching courses and the remaining 2733 had not.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).
Answer:
x= 19
If you need help with more, I'm more than happy to help you.
Answer:
answer is 5.3 cuz I am smart I learned this so I'm here to help