A histogram is like a bar graph without gaps between the rectangles. So you first create a bar graph with your labels and title, then you get rid of the gaps between the rectangles.
Answer:
Yes u did thats what i did too XD
Answer: n=58
Step-by-step explanation:
7(n-7)=3(2n+3)
We move all terms to the left:
7(n-7)-(3(2n+3))=0
We multiply parentheses
7n-(3(2n+3))-49=0
We calculate terms in parentheses: -(3(2n+3)), so:
3(2n+3)
We multiply parentheses
6n+9
Back to the equation:
-(6n+9)
We get rid of parentheses
7n-6n-9-49=0
We add all the numbers together, and all the variables
n-58=0
We move all terms containing n to the left, all other terms to the right
n=58
Answer:
[0,∞), {y|y≥0}
Step-by-step expl
The graph of y =|3x + 1| is attached.
By observation, we can see that the the least y-value that the graph can take is y =0 (i.e the x-axis) and the greatest y-value that the graph can take is positive infinity.
Hence the range is [0,∞), {y|y≥0}
