Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
96360
Step-by-step explanation:
search hours a month then multiply that by 12
First, we define variables:
x: small hat
y: medium hat
z: large hat
We now write the system of equations:
x + y + z = 47
5.50x + 6y + 7z = 302
-3x + y = 0
We can write the system in matrix form as:
Ax = b
Where,
A = [1 1 1; 5.50 6 7; -3 1 0]
b = [47; 302; 0]
x = [x; y ; z]
Solving the system we have:
x = 6
y = 18
z = 23
Answer:
the coach did purchase 23 large hats
d. 23
Where is the number line I can't solve without it
3x = 24 - 9
3x = 15
x = 15/3
x = 5
Answer: B) x= 5 or the second option.
