Answer:
a) 33.33%)
b) 135 minutes
c) 8.66 min
d) 50%
Step-by-step explanation:
a) the probability for a uniform distribution is
P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values
therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)
P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)
b) the mean (expected value) for a uniform probability distribution is
E(X) = (c+d)/2 = (120+150)/2 = 135 minutes
c) the standard deviation for a uniform probability distribution is
σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²
σ = √75 min² = 8.66 min
b) following the same procedure as in a)
P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)
Answer:
= 2(2x + 5)
Step-by-step explanation:
Given that:
= (7x + 5) - (3x - 5)
By simplifying
"-" sign before bracket will alter the inner signs
= 7x + 5 - 3x + 5
Adding like terms
= 4x + 10
By taking 2 common we get:
= 2(2x + 5)
i hope it will help you!
Answer:
73.68%
Step-by-step explanation:
To find the amount of increase subtract 33-19 to get 14.
The percent increase is the amount of increase/initial length * 100
So 14/19*100 = 73.684...
Rounding to the nearest hundredth = 73.68%
Answer:
35/8
Step-by-step explanation:
1 3/4 = 1 + 3/4 = 4/4 + 3/4 = 7/4.
So 1 3/4 ÷ 2/5 = 7/4 × 5/2 = 35/8.
Answer:
Here:
Step-by-step explanation:
