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Mademuasel [1]
2 years ago
10

Worth 10 points, please help.:):):)

Mathematics
2 answers:
beks73 [17]2 years ago
8 0
 < is the answer because the bigger number the sum is going to be bigger than the average
Law Incorporation [45]2 years ago
7 0
It is less than sign which is A
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Why is this statement false?<br> If a number has 2 and 4 as factors, then it has 8 as a factor.
Andrew [12]

Answer:

It is false

Step-by-step explanation:

It is false because 12 has the factors of 2 and 4 but 8 is not a factor of 12.

6 0
2 years ago
What is 600% written as a decimal?
Verdich [7]

Answer: 6

Step-by-step explanation: look it up

5 0
2 years ago
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Tonia and trinny are twins. Their friends give them identical cakes for their birthday. Tonia eats 1/8 of her cake and trinny ea
Nikitich [7]

Answer:

\frac{7}{12} of the cake

Step-by-step explanation:

add \frac{1}{8} and \frac{1}{6} to see the total amount of cake eaten.

a. find the common denominator: 8 x 3 = 24 and 6 x 4 = 24

b. multiply accordingly to get the correct numerator: \frac{3}{24} + \frac{4}{24}

c. add: \frac{3}{24} + \frac{4}{24} = \frac{7}{24}

subtract found value from total to find left over cake.

a. 24 - 7 = 14

simplify.

a. \frac{14}{24} = \frac{7}{12}

You are left with \frac{7}{12} of the cake.

8 0
3 years ago
Please help me thank u
finlep [7]
It would be A=18 because of the equation a^2+b^2=c^2.
3 0
3 years ago
In a recent​ poll, 44​% of survey respondents said​ that, if they only had one​ child, they would prefer the child to be a boy.
viva [34]

Answer:

a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

Step-by-step explanation:

If 71 out of 150 prefer boy child

The probability that the 71 will prefer boy child is

= 71/150

The actual percentage is

(71/150)*100%

= 47.33%

This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.

5 0
3 years ago
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