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3 years ago

15

Given the function LaTeX: f\left(x\right)=-5x^2-x+20f ( x ) = − 5 x 2 − x + 20, find LaTeX: f\left(2\right)f ( 2 ). Group of ans

wer choices -2 -28 -12 38

1 answer:

BartSMP [9]3 years ago

6 0

The value of f(2) is -2 ⇒ 1st answer

Step-by-step explanation:

The form of the quadratic function is;

f(x) = ax² + bx + c, where

a is the coefficient of x²
b is the coefficient of x
c is the numerical term
x is the domain of the function and f(x) is the range of the function

∵ f(x) = -5x² - x + 20

- f(2) means value f(x) at x = 2

∵ x = 2

- Substitute x in the function by 2 to find f(2)

∵ f(2) = -5(2)² - (2) + 20

∴ f(2) = -5(4) - 2 + 20

∴ f(2) = -20 - 2 + 20

∴ f(2) = -2

The value of f(2) is -2

Learn more:

You can learn more about the function in brainly.com/question/12363217

#LearnwithBrainly

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4 years ago

Read 2 more answers

So i need help with the question below.

Shkiper50 [21]

Answer:

Option (1)

Step-by-step explanation:

Option (1)

$3\frac{3}{9}+7\frac{6}{11}=10\frac{87}{99}$

$3\frac{3}{9}+7\frac{6}{11}$ $=3+\frac{3}{9}+7+\frac{6}{11}$

$=(3+7)+(\frac{3}{9}+\frac{6}{11})$

$=10+(\frac{3}{9}\times \frac{11}{11})+(\frac{6}{11}\times \frac{9}{9})$

$=10+(\frac{33}{99}+\frac{54}{99})$

$=10+\frac{87}{99}$

$=10\frac{87}{99}$

True.

Option (2)

$2\frac{3}{8}+6\frac{4}{5}=8\frac{12}{40}$

$2\frac{3}{8}+6\frac{4}{5}=2+\frac{3}{8}+6+\frac{4}{5}$

$=(2+6)+(\frac{3}{8}+\frac{4}{5})$

$=(8)+(\frac{3}{8}\times \frac{5}{5} +\frac{4}{5}\times \frac{8}{8})$

$=8+(\frac{15}{40}+\frac{32}{40})$

$=8+\frac{47}{40}$

$=8+\frac{40}{40}+\frac{7}{40}$

$=8+1+\frac{7}{40}$

$=9+\frac{7}{40}$

$=9\frac{7}{40}$

False.

Option(3)

$3\frac{3}{7}+4\frac{2}{3}=7\frac{2}{21}$

$3\frac{3}{7}+4\frac{2}{3}=(3+\frac{3}{7})+(4+\frac{2}{3})$

$=(3+4)+(\frac{3}{7}+\frac{2}{3})$

$=7+(\frac{3}{7}\times \frac{3}{3} +\frac{2}{3}\times \frac{7}{7})$

$=7+(\frac{9}{21}+\frac{14}{21})$

$=7+(\frac{23}{21})$

$=7+(\frac{21}{21}+\frac{2}{21})$

$=8+\frac{1}{21}$

$=8\frac{1}{21}$

False.

Option (4)

$4\frac{5}{6}+5\frac{5}{7}=9\frac{10}{13}$

$4\frac{5}{6}+5\frac{5}{7}=4+\frac{5}{6}+5+\frac{5}{7}$

$=(4+5)+(\frac{5}{6}+\frac{5}{7})$

$=9+(\frac{5}{6}\times \frac{7}{7}+\frac{5}{7}\times \frac{6}{6})$

$=9+(\frac{35}{42}+\frac{30}{42})$

$=9+\frac{65}{42}$

$=9+(\frac{42}{42}+\frac{23}{42})$

$=9+1+\frac{23}{42}$

$=10\frac{23}{42}$

False.

Therefore, Option (1) is the answer.

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3 years ago

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Arte-miy333 [17]

The points which satisfy the inequalities in discuss are; Choices D (7,10) and F(8,17).

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2 years ago