Question

P(x) = 2x² + 1 What is the inverse for p(x)?

Answer 1

Answer:

$P^{-1} (x)=\sqrt{\frac{x-1}{2} }$

Step-by-step explanation:

1. $P(x)=2x^{2} +1$

2. $y=2x^{2} +1$

3.$x=2y^{2} +1$

4.$2y^{2} =x-1$

5.$y^{2} =\frac{x-1}{2}$

6.$y=\sqrt{\frac{x-1}{2} }$

7.$P^{-1} (x)=\sqrt{\frac{x-1}{2} }$