Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Answer: the Jones family paid $164
Step-by-step explanation:
Let x represent the one time charge that smith lake boat rentals charge for cleaning.
The bengal family rented a boat from 11 am- 6:30pm and paid $226.50. This means that the number of hours for which they rented the boat is
11 - 6:30/= 7.5 hours
Therefore,
25 × 7.5 + x = 226.5
187.5 + x = 226.5
x = 226.5 - 187.5
x = $39
If the jones family rented a boat from 8am-1pm, the number of hours would be 5 hours.
The amount that they paid is
39 + 5 × 25 = 39 + 125
= $164
Answer:
You gotta deserve it
Step-by-step explanation:
