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Paraphin [41]
3 years ago
9

Which linear inequality is represented by the graph?​

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

y ≥ \frac{1}{3}x - 1

Step-by-step explanation:

First, determine the slope of the line. We can see that the slope is \frac{1}{3}, because the slope has less than 1 y interval per every x interval. This means that the line is less steep. There are only 2 slope choices, \frac{1}{3}, -\frac{1}{3}\\, and 3. We can tell that the slope is positive, but it must be \frac{1}{3}\\ because it is clearly less steep than a 3 slope line.

Now, look at the portion that is shaded. It is above the line, and this means that y is greater than the equation given. We can tell it is greater than or equal to, because the line that represents the equation is shaded as well. If it was only greater than and not equal to, the line would not be shaded.

Hope this helps ! :) Please feel free to ask me any questions!

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Since the quadratic is in factored form = 0 , in order to solve, the factors are set =0 and solved for x. true or false
gulaghasi [49]
True it’s 0 am I right
4 0
3 years ago
Give the slope-intercept form of the equation of the line that is perpendicular to –7x + 5y = 12 and contains P(–7, 4).
kherson [118]

y = - \frac{5}{7} x - 1

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange - 7x + 5y = 12 into this form

add 7x to both sides

5y = 7x + 12 ( divide all terms by 5 )

y = \frac{7}{5} x + \frac{12}{5} ← in slope- intercept form

with slope m = \frac{7}{5}

given a line with slope m then the slope of a line perpendicular to it is

perpendicular slope = - \frac{1}{m} = - \frac{5}{7}

The partial equation of the perpendicular line is

y = - \frac{5}{7} x + c

to find c substitute (- 7, 4 ) into the partial equation

4 = 5 + c ⇒ c = 4 - 5 = - 1

y = - \frac{5}{7} x - 1 ← in slope- intercept form


8 0
3 years ago
2. If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. Find the first term and the 20th te
alexandr1967 [171]

the first term is 2 and the 20th term is 1048576 .

<u>Step-by-step explanation:</u>

Here we have , If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. We need to Find the first term and the 20th term. Let's find out:

We know that Sum of a GP is :

⇒ S_n = \frac{a(r^n-1)}{r-1}

So ,Sum of first 12 terms is :

⇒ S_1_2 = \frac{a(2^{12}-1)}{2-1}

⇒ 8190=a(2^{12}-1)

⇒ \frac{8190}{4095}=a

⇒ a=2

Now , nth term of a GP is

⇒ a_n = ar^{n-1}

So , 20th term is :

⇒ a_2_0 = 2(2)^{20-1}

⇒ a_2_0 = (2)^{20}

⇒ a_2_0 = 1048576

Therefore , the first term is 2 and the 20th term is 1048576 .

4 0
3 years ago
Two lines, A and B, are represented by the following equations:
liraira [26]
D, because if u plug it in both equation, u will get the same solution.
y=x-1
2=3-1
2=2

y=-3x+11
2=-3(3)+11
2=-9+11
2=2

Hope this helps!
4 0
3 years ago
Evaluate the definite integral
Georgia [21]
\displaystyle\int_{x=9}^{x=10}x\sqrt{x-9}\,\mathrm dx

Let y=x-9, so that x=y+9 and \mathrm dx=\mathrm dy. The integral is then equivalent to

\displaystyle\int_{y=0}^{y=1}(y+9)\sqrt y\,\mathrm dy=\int_0^1(y^{3/2}+9y^{1/2})\,\mathrm dy=\dfrac{32}5
7 0
3 years ago
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