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shusha [124]
1 year ago
9

Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?

Mathematics
1 answer:
cluponka [151]1 year ago
7 0

The rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6).

<h3>What is translation?</h3>

When a line is translated, it means the line is moved from one position to another. The coordinate for triangle ABC are A(-3 ,4) , B(-4,1) and C(-2,1).

The coordinate of triangle A'B'C' is A'(4,-2), B'(3,-5), and C'(5,-5).

From above, it can be seen that the image A'B'C' is obtained from the pre-image ABC by translating the vertices of the image by 7 units to the right and 6 units down.

Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6)

Hence, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6).

Learn more about translation on:

brainly.com/question/12861087

#SPJ1

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Which expression is equivalent to x² + 2x + 2?
melisa1 [442]

Answer:

(x+1-i)(x+1+i)

Step-by-step explanation:

(x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2

4 0
1 year ago
1.
oksian1 [2.3K]

Answer:

Answer is 2

{ \rm{4x + 2 > 10}} \\  \\ { \rm{4x < 8}} \\  \\ { \rm{x < 2}}

6 0
2 years ago
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Choose where it is a function or not a function also choose what is the range and the domain
kow [346]
Not a function because of the vertical line test.
Domain is [-2,∞] since the left most point is -2 and the right is unbounded.
Range is (-∞,∞) since it is not bounded in terms of y.
7 0
2 years ago
Samuel is trying to construct the inscribed circle of a triangle.
Yuki888 [10]

The next step to complete the construction will connect the in-center to one of the sides of the triangle.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

Samuel is trying to construct the inscribed circle of a triangle.

Using the angle bisectors to find the in-center.

Where two angles bisector meets, the point called in-center.

Next step will be: connect the in-center to one of the sides of the triangle.

Thus, the next step to complete the construction will be connect the in-center to one of the sides of the triangle.

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3 0
2 years ago
In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the
Sidana [21]

Step 1    

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

\frac{TR}{TP} =\frac{TS}{QT}

solve for TS

TS =\frac{TR*QT}{TP}

we have

RP=2\ cm\\TP=18\ cm\\QT=27\ cm

TR=TP+RP\\TR=18+2=20\ cm

substitute

TS =\frac{20*27}{18}  

TS =30\ cm

Step 2

<u>Find the value of SQ</u>

we know that

SQ=TS-QT

we have

TS =30\ cm

QT=27\ cm

substitute

SQ=30\ cm-27\ cm=3\ cm

therefore

<u>the answer is</u>

the value of SQ is 3\ cm

6 0
2 years ago
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