Which rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C'?
1 answer:
The rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6).
<h3>What is translation?</h3>When a line is translated, it means the line is moved from one position to another. The coordinate for triangle ABC are A(-3 ,4) , B(-4,1) and C(-2,1).
The coordinate of triangle A'B'C' is A'(4,-2), B'(3,-5), and C'(5,-5).
From above, it can be seen that the image A'B'C' is obtained from the pre-image ABC by translating the vertices of the image by 7 units to the right and 6 units down.
Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6)
Hence, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y - 6).
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Answer:
Center: (-1,8)
Radius: 1
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:
Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is
Therefore:
h=-1
k=8
Then, the center is (-1,8) and radius is 1.
You can graph the circle with its center at the (-1,8) and a radius of 1 as you can see in the figure attached.
