Simplify: x^0 y^-3 / x^2 Y^-1

2 answers:

6 0

But if you're adding them the answer would be $1/ x^{2}y^2$

3 0

<span>x^0 y^-3 / x^2 y^-1
= 1 / </span> x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2<span>
= 1/(x^2 y^2)</span>

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