Answer:
Option(a) and option(d) are the correct answer for the given question.
Explanation:
In this question options are missing so the options of this question is given below.
a Behaviour analysis can be done at the machine speeds.
b Search results are returned by the quicker than using traditional method of
filtering
c Adapted the ever-changing attributes of an threat.
d choose the most appropriated web application for the given task.
Web Application Firewalls are the effective which helps in learning for the machines to make it modernized. So, that's why the analyzing of the behavior could be done at the speed of the machine and also select that appropriate web applications for the following tasks. That's why the following options are true for the given question.
Answer:
4 * 8 * 6 = 192
Explanation:
First menu = 4 selections
second menu = 8 selections
third menu = 6 selections
we need to find how many configuration can the game be played, we just here multiply all the selections and find the answer
4 * 8 * 6 = 192
Hello alanagarcia. When posting coding questions you should show some of the work you have tried. After all this is in the college section. Normally I will delete these types of posts if no work has been shown or if the poster does not tell us what type of language they are using. Since you gave us the language, the following code will do what you need it to do. Next time show a little work please. TY.
monthlist = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December']
for month in monthlist:
if "J" in month:
print(month)
Hi there!
I have taken a computer fundamentals class before and they did skim over the topic, but they did not go into depth on it at all. If you really want to learn about that stuff I suggest you find a course that is specifically on that topic or something that is closer related then a general <span>computer fundamentals course.
-Your friend in tech,
</span>ASIAX <span> </span><span>Frequent Answerer</span>
Answer:
#include<iostream>
using namespace std;
void main()
{
int townA_pop,townB_pop,count_years=1;
double rateA,rateB;
cout<<"please enter the population of town A"<<endl;
cin>>townA_pop;
cout<<"please enter the population of town B"<<endl;
cin>>townB_pop;
cout<<"please enter the grothw rate of town A"<<endl;
cin>>rateA;
cout<<"please enter the grothw rate of town B"<<endl;
cin>>rateB;
while(townA_pop < townB_pop)//IF town A pop is equal or greater than town B it will break
{
townA_pop = townA_pop +( townA_pop * (rateA /100) );
townB_pop = townB_pop +( townB_pop * (rateB /100) );
count_years++;
}
cout<<"after "<<count_years<<" of years the pop of town A will be graeter than or equal To the pop of town B"<<endl;
}
Explanation: