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tigry1 [53]
3 years ago
10

This is the formula for the future worth of an investment over time with consistent additional monthly payments and a steady rat

e of return. This can give you a bonus of 200 points. You will not be penalized if you do not do this nor will you be penalized if it is incorrect. This is a challenging problem because of all the mathematics involved. Let’s see how good you really are. FV = PV (1+ r/k) nk +PMT * [ (1+r/k) nk −1] * (1+ r/k) r/k FV : future value PV : initial value R : interest rate K : regular periodic investments
• Annually,
• Semi-annually,
• Quarterly,
• Monthly PMT:
payment (installments) N : years Problem: You wish to start putting money away for your retirement (far-fetched, huh) anyway, how much would you have after 45 years if you started with an initial payment (PV) of $1000.00 and invested $250 (K) monthly. The dividend payments are 6% (R)and you invest $250 a month for the next 45 years. Your investment has an annual rate of return (R) of 6%. Show how you would break this problem down into pieces (your pseudo code). Then show your source code and display your initial investment, rate of return, length of time, monthly payments into the account and the final outcome. Show how much money you invested and what the final amount is, you’ll be surprised. HINT: try doing this problem manually first
Computers and Technology
1 answer:
stepladder [879]3 years ago
4 0

Answer:

The code is given in C++ below

Explanation:

#include <iostream>

using namespace std;

int main()

{

float fv,pv,r,k,n,pmt,totalmoneyinvested;

pv=1000.00;

r=6/100;

k=12; //The value of k should be 12 for monthly installments

n=45;

pmt=250;

totalmoneyinvested=pv+(pmt*12*45); //The total money you invested

 

fv=pv*(1+r/k)*n*k+pmt*((1+r/k)*n*k-1)*(1+r/k)*r/k;

 

cout<<"Initial Investment:"<<" $"<<pv;

cout<<"\nRate Of Return:6%";

cout<<"\nLength of Time:"<<n<<"year";

cout<<"\nMonthly Payment:"<<" $"<<pmt;

cout<<"\nFinal Amount:"<<" $"<<fv;

cout<<"\nThe Money You Invested Is $"<<totalmoneyinvested<<" And The Final Amount Is $"<<fv;

return 0;

}

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ERP implementation probably will not require:
Mamont248 [21]

Answer:

c. just a few weeks to install.

Explanation:

ERP is known as Enterprise Resource Planning.ERP implementation involves software installation, transfer of the financial data to the new system, configuration of the users and processes and training the users on the software.

It also involves upgrades after installation,cross-functional teams, intensive training, high funding for both initial cost and maintenance. This whole process usually takes place between 6 months to 2 years. This makes option C which says it takes few weeks to install incorrect.

3 0
3 years ago
Read 2 more answers
Write a C++ programthat returns the type of a triangle (scalene, equilateral,or
bixtya [17]

Answer:

#include<iostream>

using namespace std;

int main(){

   //initialize

   int a, b,c;

   //print the message

   cout<<"Enter the three sides of the triangle: "<<endl;

   //store in the variables

   cin>>a>>b>>c;

   //if-else statement for checking the conditions  

   if(a == b && b == c && a == c){

       cout<<"\nThe triangle is equilateral";

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Explanation:

Create the main function and declare the three variables for the length of the sides of the triangle.

print the message on the screen for the user. Then the user enters the values and its store in the variables a, b, and c.

use the if-else statement for checking the conditions.

Equilateral triangle: all sides of the triangle are equal.

if condition true, print the equilateral triangle.

Scalene triangle: all sides of the triangle are not equal.

if condition true, print the Scalene triangle.

if both conditions is not true, then, the program moves to else part and print isosceles.

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Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

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What is a close syllable
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Computer simulation is just like training for example before pilot fly plane they got training from computer simulation it's just like video lecture
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