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3 years ago

Math question please show work for brainliest :)

Mathematics

2 answers:

Marizza181 [45]3 years ago

5 0

The answer would be D.

Since we know absolute value shows the distance between zero and a number,

and it doesn't matter if the number is positive or negative as long as they are inside these "l l". So if we add -9 or -7 to 8, the result would be 1 and -1. And when we take it out of these "l l", the number should always be positive.

*Sorry about these "l l", i don't what they call it in English.

katrin2010 [14]3 years ago

3 0

|x+8| = 1

x + 8 = 1

x = -7

-(x+8) = 1

-x - 8 = 1

-x = 9

x = -9

Answer

D. x = -7, - 9

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What is 33 %of what number is 1.45

Anna007 [38]

To find 33% of 1.45 we have to tranform 33% into decimal of traction
33% is 0.33 or $\frac{33}{100}$ and multiply if by 1.45
so
0.33*1.45=0.4785
or
1.45* $\frac{33}{100}= \frac{957}{2000}$

5 0

3 years ago

Determine the range of the function graphed below.<br> Answer choices are below as well

Softa [21]

Answer:

The range of the function will be (- ∞, 4].

Step-by-step explanation:

See the graph attached.

Here we have to get the range of the graphed function.

The value of y in the graphed function varies in the range of less than or equal to 4.

Because the graph of the function does not move beyond 4 towards +∞.

Therefore, the range of the function will be (- ∞, 4]. (Answer)

5 0

3 years ago

PLEASE SOLVE THIS PROBLEM

schepotkina [342]

Answer:

18) Area= 5*5/2=25/2=12.5 unit ^2

19) Area=AB^2V3/4=8a^2*V3/4=2V3a^2

Step-by-step explanation:

18. A(-3,0)

B(1,-3)

C(4,1)

AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5

AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2

BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5

so AB=BC=5

and AC^2=AB^2+BC^2

so trg ABC is an isosceles right angle triangle (<B=90)

Area= 5*5/2=25/2=12.5 unit ^2

19. A(a,a)

B(-a,-a)

C(-V3a, V3a)

AB=V(a+a)^2+(a+a)^2=V4a^2+4a^2=V8a^2

AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2

BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2

so AB=AC=BC

Area=AB^2V3/4=8a^2*V3/4=2V3a^2

7 0

2 years ago

If g(x)=4x^2-16 were shifted 5 units to the right and 2 down, what would the new equation be?

Eduardwww [97]

Try this, pls:
When any line on graph is moved to the right, for 'x' must be '-'.
When one is moved down, for 'y' must be '-'.
Finaly: y=4(x-5)²-18.
Answer: A.

4 0

3 years ago

Read 2 more answers

Consider parent function f(x)=e^x and the transformes function g(x)= -1/2e^3x+4, quantitatively explain the transformations to t

kolezko [41]

Answer: reflection across the x-axis

vertical shrink by a factor of 1/2

horizontal shrink by a factor of 1/3

vertical shift up 4 units

<u>Step-by-step explanation:</u>

$\text{Note:}\ g(x) = -Ae^{Bx-C}+D\\\bullet \quad \text{- represents a reflection across the x-axis}\\\\\bullet \quad \text{A represent a vertical stretch by a factor of A (shrink if}\ |A| < 1)\\\\\bullet \quad \text{B represents a horizontal stretch by a factor of}\ \dfrac{1}{B}\ (\text{shrink if}\ |B| >1) \\\\\bullet \quad \text{C represents a horizontal shift of C units}\ (\text{+ is right, - is left}) \\\\\bullet \quad \text{D represents a vertical shift of D units}\ (\text{+ is up, - is down})$

$\text{Parent function:}\ f(x)=e^x\\\text{Transformed function:}\ g(x)=-\dfrac{1}{2}e^{3x}+4\\$

The transformed function has the following:

Negative: reflection across the x-axis

A = 1/2 vertical shrink by a factor of 1/2

B = 3 horizontal shrink by a factor of 1/3

C = 0 no horizontal shift

D = 4 vertical shift of 4 units up

6 0

3 years ago