To determine the probability that exactly two of the five marbles are blue, we will use the rule of multiplication.
Let event A = the event that the first marble drawn is blue; and let B = the event that the second marble drawn is blue.
To start, it is given that there are 50 marbles, 20 of them are blue. Therefore, P(A) = 20/50
After the first selection, there are 49 marbles left, 19 of them are blue. Therefore, P(A|B) = 19/49
Based on the rule of multiplication:P(A ∩ B) = P(A)*P(A|B)P(A ∩ B) = (20/50) (19/49)P(A ∩ B) = 380/2450P(A ∩ B) = 38/245 or 15.51%
The probability that there will be two blue marbles among the five drawn marbles is 38/245 or 15.51%
We got the 15.51% by dividing 38 by 245. The quotient will be 0.1551. We then multiplied it by 100% resulting to 15.51%
Answer:
161.3000
Step-by-step explanation:
1. <span>12(x − 4)
</span>2. <span>x5
</span>3. <span>The quotient of some number and ten
</span>4. <span>b − 8
</span>5. <span>The quotient of four times some number and six
</span>6. <span>3x + 7
1. x and -4 are multiplied by 12
2 raided to this 5th power is an exponent
3 quotient means division
4 less than means subtraction
5 division means quotient, list numerator first then the denominator
6 product of is multiplication and more is an addition.</span>
For the first digit you are choosing from 2 digits
for the second digit you are choosing from 2 digits
for the third digit you are choosing from 2 digits
2*2*2=8
111
110
011
101
000
001
100
010
However......
A number doesn't usually start with a 0 or 0s.
Therefore, if you want 3-digit numbers and not just permutations using 0 and 1, then you must eliminate
011, 000, 001, and 010
Seeing that the first digit can't be 0, you choose from 1, then 2, and then 2 digits again; 1*2*2=4 numbers
You choose which answer best suits your problem.
Answer:
17
Step-by-step explanation:
6 + 11 = 17
Sum (addition of 2 numbers)
