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3 years ago

Solve and then use estimation to make sure your answer is reasonable.

Mathematics

1 answer:

Vinil7 [7]3 years ago

3 0

114.5 hours = 6870 minutes
∴ 6870 ÷ 22 = 312.2727273

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find 2 numbers the exact answer is between, for example 3 x 567. how do you do this problem and what is the answer?

kramer

Here is an example I did of the problem hope it helps let me know if you need anything else~!

~Cecildoesscience

6 0

3 years ago

Someone Please Help Quickly! Its an Easy Question

Paul [167]

Answer:

$y=\frac{2}{3}x-6$

Step-by-step explanation:

Use the slope-intercept form:

$y=mx+b$

m is the slope and b is the y-intercept. Looking at the graph, you can find the y-intercept. The y-intercept is the point where x equals 0:

$b=-6$

$y-intercept=(0,-6)$

To find the slope, take any two points from the line:

$(6,-2)(3,-4)$

Use the slope formula for when you have two points:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{rise}{run}$

The rise over run is the change in the y-axis over the change of the x-axis. Insert the appropriate values:

$(6(x_{1}),-2(y_{1})\\(3(x_{2}),-4(y_{2})$

$\frac{-4-(-2)}{3-6}$

Simplify parentheses (two negatives makes a positive):

$\frac{-4+2}{3-6}$

$\frac{-2}{-3}$

Simplify (two negatives make a positive):

$m=\frac{2}{3}$

The slope is $\frac{2}{3}$ and the y-intercept is $-6$ . Insert these into the equation:

$y=\frac{2}{3}x-6$

Finito.

7 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$