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kondaur [170]
2 years ago
12

Elias and Niko are polishing the silver at the heritage museum. Elias could polish all the silver himselfin 40 minutes. That tas

k would take Niko 50 minutes to complete alone. Which table is filled in correctly and could be used to determine how long it would take if Elias and Niko polished the silver together?

Mathematics
1 answer:
Verizon [17]2 years ago
4 0
Ummmmmmmmm i'd say its D
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Can someone please help me with #3?
kap26 [50]

Answer:


Step-by-step explanation:

First, make sure you know which section of the number line you want as 1 and 2. Next, put 0.25 not right at 0 but very close, then put 0.75 farther but not too much from 0.25. Then for the decimal 1.99 put that very close to where you marked the 2 but, not on the 2. Finally, put 2.03  very close to 2 but not exactly on the 2. Also, make sure that the number line is marked evenly.

7 0
2 years ago
Is 2/11 bigger than 3/12
Tju [1.3M]
2/11 ≈ 0.18    3/12 = 0.25. 

So the answer is no, 2/11 isn't bigger than 3/12. 

I hope this helps!
6 0
2 years ago
Read 2 more answers
Please help me!!!! Super confused
valkas [14]
The correct answer to 38 is B
4 0
2 years ago
Find each measure <br><br> Please help me
Crazy boy [7]

Answer:

see explanation

Step-by-step explanation:

∠ YXW = ∠ ZXV ( vertically opposite angles ) , so

4a + 15 = 2a + 65 ( subtract 2a from both sides )

2a + 15 = 65 ( subtract 15 from both sides )

2a = 50 ( divide both sides by 2 )

a = 25

Then

(7)

∠ ZXV = 2a + 65 = 2(25) + 65 = 50 + 65 = 115°

(8)

∠ YXW = ∠ ZXV = 115°

∠ ZXY and ∠ ZXV are adjacent angles and sum to 180° , that is

(9)

∠ ZXY = 180° - 115° = 65°

(10)

∠ VXW = ∠ ZXY = 65° ( vertically opposite angles

8 0
2 years ago
The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu
PSYCHO15rus [73]

Answer:

a) I(95,50) = 73.19 degrees

b) I_{T}(95,50) = -7.73

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

a) Calculate I at (T ,H) = (95, 50).

I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19 degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is I_{T}(T,H). So

I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}

I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H

I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73

8 0
3 years ago
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