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pshichka [43]
3 years ago
7

Allie bought a 5 pound bag of trail mix. she gave 12 Oz of trail mix to Justin. then she put the rest of the trail mix to into s

mall bags to use for snacks. if each bag contained 4 Oz of trail mix, how many small bags of trail mix did Allie make?
Mathematics
2 answers:
nadya68 [22]3 years ago
7 0
5 lbs. = 80 oz.

80 - 12 = 68 oz.

68 / 4 = 17 bags

Hope this helps!
disa [49]3 years ago
4 0
Hey there, 5Ibs=80 oz, I got that because 16*5=80, 80-12=68. So, 68÷4=17. Thus, your final answer is 17.
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3 décimas multiplicadas por 100 equivalen a 300 milésimas
larisa86 [58]

3/10 *1 = 3/10  so 3/10 * (100/100) = 300/1000 = 3/10

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3 years ago
A random sample of 40 college students has a mean earnings of​ $3120 over the summer months. Assume the population standard devi
PSYCHO15rus [73]

Answer:

A normal distribution or z-test is used to construct a confidence interval.

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $3120

Sample size, n = 40

Population standard deviation, σ = $677

The distribution of earnings of college is a normal distribution.

Conditions:

  • Since we are given the population standard deviation and the the sample size is also greater than 30.

Conclusion:

Thus, we use a normal distribution or z-test to construct a confidence interval.

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3 years ago
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3 years ago
Read 2 more answers
Many states assess the skills of their students in various grades. One program that is available for this purpose is the Nationa
Nataly [62]

Answer:

A score of 314 is needed to be in the top 25% of students who take this exam.

Step-by-step explanation:

We are given that one of the tests provided by the NAEP assesses the reading skills of twelfth-grade students. In recent years, the national mean score was 289 and the standard deviation was 37.

Let X = <u><em>scores of the tests provided by the NAEP</em></u>

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = national mean score = 289

           \sigma = standard deviation = 37

Now, we have to find how high a score is needed to be in the top 25% of students who take this exam, that means;

            P(X > x) = 0.25     {where x is the required score}

            P( \frac{X-\mu}{\sigma} > \frac{x-289}{37} ) = 0.25

            P(Z > \frac{x-289}{37} ) = 0.25

In the z table, the critial value of z that represents the top 25% of the area is given as 0.6745, that is;

                        \frac{x-289}{37}=0.6745

                        {x-289}=0.6745\times 37

                        x = 289 + 24.96 = 313.96 ≈ 314

Hence, a score of 314 is needed to be in the top 25% of students who take this exam.

7 0
3 years ago
The harmonic mean of two real numbers x and y equals 2xy/(x + y). By computing the harmonic and geometric means of different pai
olasank [31]

Answer:

Conjecture :  2xy / ( x + y ) ≤  √xy

Step-by-step explanation:

Harmonic mean of  x and y = 2xy/( x + y )

<u>Formulate a conjecture about their relative sizes </u>

we will achieve this by computing harmonic and geometric means

Geometric mean = √xy

harmonic mean = 2xy/( x + y )

Conjecture :  2xy / ( x + y ) ≤  √xy

attached below is the proof

7 0
2 years ago
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