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pshichka [43]
3 years ago
7

Allie bought a 5 pound bag of trail mix. she gave 12 Oz of trail mix to Justin. then she put the rest of the trail mix to into s

mall bags to use for snacks. if each bag contained 4 Oz of trail mix, how many small bags of trail mix did Allie make?
Mathematics
2 answers:
nadya68 [22]3 years ago
7 0
5 lbs. = 80 oz.

80 - 12 = 68 oz.

68 / 4 = 17 bags

Hope this helps!
disa [49]3 years ago
4 0
Hey there, 5Ibs=80 oz, I got that because 16*5=80, 80-12=68. So, 68÷4=17. Thus, your final answer is 17.
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PLEASE HELP!!!<br> SHOW YOUR ANSWER AND REASONING HURRY PLEASE
boyakko [2]
R u in an assessment or something.U need to chill boi.
6 0
2 years ago
Shawna has 4/5 ounces of juice. She drinks 3/4 of it. How much is left
Bezzdna [24]

Answer:

0.05

Step-by-step explanation:

I turned the fractions into decimals. to do that your do exactly as it tells you!

4 divided by 5 = 0.8

so she has 0.8 ounces of juice (That not alot lol I would not be satisfied) now for how much she drank...

3 divided by 4 =0.75

0.80 - 0.75 = 0.05

She drank 0.05 ounces

Hope this helped! Please mark as brainliest! Thanks! If you need me to turn 0.05 in a fraction i can do that.

4 0
3 years ago
In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0
3 years ago
So yeah. . .. idk how to do this
kipiarov [429]

<em>Please </em>use for reference. Merci.

To find rate of change simply divide y/x.

hour 2: 56/2=28

hour 4: 125/4~about 31.3 or 31

hour 5: 164/5=32.8 or ~ 33

hour 8: 271/8 ~ about 34 or 33.875

hour 13: 404/13 ~ about 31 or 31.0769231

What numbers are the largest?

hours 5 and 8

Thus, the correct answer was option C.

5 0
3 years ago
Let u= &lt; 4, -7&gt;, v= &lt;5, 3&gt; find the component form for the vector -4u + 2v
Nata [24]

Answer:

-4u+2v = <-6, 34>

Step-by-step explanation:

u = <4, -7) → -4u = <-16, 28>

v = <5, 3> → 2v = <10, 6>

-4u+2v =  <-16, 28> + <10, 6> = <-6, 34>

5 0
3 years ago
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