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Leya [2.2K]
2 years ago
8

Find the value of x in the following diagram, 3x + 10 Here, B and D are points of tangency.

Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0

<u>Given</u>:

The given circle with center at C. The lines AB and AD are tangents to the circle C.

The length of AB is (3x + 10)

The length of AD is (7x - 6)

We need to determine the value of x.

<u>Value of x:</u>

Since, we know the property of tangent that, "if two tangents from the same exterior point are tangent to a circle, then they are congruent".

We shall determine the value of x using the above property.

Thus, we have;

AB = AD

Substituting the values, we get;

3x+10=7x-6

Subtracting both sides of the equation by 7x, we get;

-4x+10=-6

Subtracting both sides of the equation by 10, we get;

-4x=-16

Dividing both sides of the equation by -4, we get;

x=4

Thus, the value of x is 4.

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Answer:

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Step-by-step explanation:

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Which measurement is closest to the volume of the cone in cubic inches? 6in 16 in
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2 years ago
Does anyone know the answer to this ???
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<h2>C. ΔQRS ≅ ΔGFE </h2>

ΔQRS ≅ ΔGFE because :

∠Q = ∠G = 55°( corresponding part )

∠R = ∠F = 60° ( corresponding part )

∠S = ∠E = 65° ( corresponding part )

QS = GE = 16 ( corresponding part )

Therefore , the correct answer is :-

<h3>C. ΔQRS ≅ ΔGFE </h3>

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3 years ago
I’m not very sure how to simplify the two bottom rows, can someone help me?
love history [14]

Answer:

The simplification is done below.

Step-by-step explanation:

(\sin(\frac{\pi}{6})\cos(\frac{\pi}{4}) - \sin(\frac{\pi}{4})\cos(\frac{\pi}{6}))^{2}

=  (\frac{1}{2} \times \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2})^{2}

=((\frac{1}{2\sqrt{2}}) \times (1 - \sqrt{3}))^{2}

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