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Pani-rosa [81]
3 years ago
14

The amount of money Deon earns working at a store is given in the table.

Mathematics
1 answer:
Sloan [31]3 years ago
3 0
Answer:

C.

Explanation:
I had the quiz as well :)
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Use the quadratic formula to find both solutions to the quadratic equation
yanalaym [24]

Answer:

b

Step-by-step explanation:

took the test

7 0
3 years ago
The mean annual incomes of certified welders are normally distributed with the mean of $50,000 and a population standard deviati
garik1379 [7]

Answer:

Their welders earn $50,000 annually.

Step-by-step explanation:

Given : \mu = 50,000

           \sigma = 2000

           n = 100

          \bar{x}=50350

To Find : The ship building association wishes to find out whether their welders earn more or less than $50,000 annually.

Solution :

H_0:\mu = 50000\\H_a: \mu \neq 50000

n = 100

Since n > 30

So we will use z test

z= \frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

Substitute the values

z= \frac{50350-50000}{\frac{2000}{\sqrt{100}}}

z=1.75

Refer the z table for p value

p value = 0.9599

α= 0.05

Since p value > α

So we accept the null hypothesis .

Hence  their welders earn $50,000 annually.

4 0
3 years ago
If y’all wanna join a zoom because you bored join this
REY [17]

Answer:

I would but i can't

Step-by-step explanation:

5 0
3 years ago
Which of the following represents f(-3)? <br><br>A: 7 <br><br>B: 5 <br><br>C: 1 <br><br>D: -1 <br>​
Fed [463]

Answer:

f(-3)=-1

Step-by-step explanation:

-3 is less than 0, so you are going to use f(x)=x+2.

Plug in values:

f(-3)=-3+2\\f(-3)=-1

7 0
3 years ago
Read 2 more answers
Find the area of each shaded region each outer polygon is regular <br><br><br> See the picture
PSYCHO15rus [73]

Answer:

Area of the shaded region = 3.46 square units

Step-by-step explanation:

Measure of the interior angle of a regular polygon = \frac{(n - 2)\times180}{n}

From the picture attached,

Number of sides of the given polygon 'n' = 6

Interior angle (∠BAF) of the given polygon = \frac{(6 - 2)\times 180}{6}

                                                                       = 120°

Measure of ∠BAC = \frac{120}{4}

                              = 30°

Now we apply sine rule in ΔAGB,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{BG}{AB}

BG = AB[sin(30°)]

     = 2\times \frac{1}{2}

     = 1

By applying cosine rule in ΔABG,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

              = \frac{AG}{AB}

AG = AB[cos(30°)]

     = 2\times \frac{\sqrt{3} }{2}

     = \sqrt{3}

AC = 2(AG)

     = 2√3

Area of ΔABC = \frac{1}{2}(\text{Base})(\text{Height})

                       = \frac{1}{2}(AC)(BG)

                       = \frac{1}{2}(2\sqrt{3} )(1)

                       = \sqrt{3}

Area of the shaded region = Area of ΔABC + Area of ΔFED

                                             = 2(Area of ΔABC)

                                             = 2√3

                                             = 3.46 square units

6 0
3 years ago
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