<h3>Answer:</h3>
x = 3
<h3>Explanation:</h3>
The product of the lengths of segments from the intersection point to the circle is the same for both secants.
... 1×6 = 2×x
... 6/2 = x = 3 . . . . . divide by 2
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<em>Comment on secant geometry</em>
Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.
When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
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1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
<span>8 + 5n = -72
5n = -72 - 8
5n = - 80
n = -80/5
n = -16</span>
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