Question

Evaluate log (base 9) 27. Can someone explain this one for me so i could do some tasks on my own?

Answer 1

$log_927=log_93^3=3log_93=3log_9\sqrt9=3log_99^\frac{1}{2}\\\\=\frac{1}{2}\cdot3log_99=\frac{3}{2}$

Answer 2

You would use some properties of the logarithm. First, $log_927=log_{3^2}27=\frac{1}{2}log_327$. So, now you have $log_327$ to calculate. It's $log_33^3=3$, so the final result is $\frac{1}{2}*3=\frac{3}{2}$
Hope it helps.