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1 year ago

Write two conditionals from each biconditional

Mathematics

1 answer:

bearhunter [10]1 year ago

3 0

Two conditionals from each biconditional are

(1) A month has exactly 28 days (2) It is February
(1)Two angels are complementary (2) The measures of the angles add up to 90
(1) The area of square s^2 (2) The perimeter of the square is 4s

<h3>How to write two conditionals from each biconditional?</h3>

A biconditional statement is represented as:

if and only if p, then q

From the above biconditional statement, we have the following conditional statements

Conditional statement 1: p

Conditional statement 2: q

Using the above as a guide, the conditional statements from the biconditional statements are:

Biconditional statement 30

A month has exactly 28 days
It is February

Biconditional statement 31

Two angels are complementary
The measures of the angles add up to 90

Biconditional statement 32

The area of square s^2
The perimeter of the square is 4s

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Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

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3 years ago

I need help pls!! 20 points I need it!!

dolphi86 [110]

Answer: About 6.71 units

Step-by-step explanation:

You use the distance formula: $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$ .

Assign the the two points to the variables:

$(x_{1}, y_{1}) = (1, 3)\\(x_{2}, y_{2}) = (4, -3)$

Substitute them in the formula:

$\sqrt{(4-1)^{2}+(-3-3)^{2}}$

And solve it:

$\sqrt{(4-1)^{2}+(-3-3)^{2}}\\=\sqrt{(3)^{2}+(-6)^{2}}\\=\sqrt{9+36}\\=\sqrt{45}\\=6.71$

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