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makvit [3.9K]
1 year ago
10

Write two conditionals from each biconditional

Mathematics
1 answer:
bearhunter [10]1 year ago
3 0

Two conditionals from each biconditional are

  • (1) A month has exactly 28 days (2) It is February
  • (1)Two angels are complementary  (2) The measures of the angles add up to 90
  • (1) The area of square s^2 (2) The perimeter of the square is 4s

<h3>How to write two conditionals from each biconditional?</h3>

A biconditional statement is represented as:

if and only if p, then q

From the above biconditional statement, we have the following conditional statements

Conditional statement 1: p

Conditional statement 2: q

Using the above as a guide, the conditional statements from the biconditional statements are:

<u>Biconditional statement 30</u>

  • A month has exactly 28 days
  • It is February

<u>Biconditional statement 31</u>

  • Two angels are complementary
  • The measures of the angles add up to 90

<u>Biconditional statement 32</u>

  • The area of square s^2
  • The perimeter of the square is 4s

Read more about biconditionals at

brainly.com/question/27738859

#SPJ1

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8

Step-by-step explanation:

Since the formula is b × h ÷ 2, just plug in the numbers from the question

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2 × 8 ÷ 2 = 8

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A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:
Lady bird [3.3K]

Using derivatives, it is found that:

i) v(t) = 3t^2 - 6t

ii) 9 m/s.

iii) a(t) = 6t - 6

iv) 6 m/s².

v) 1 second.

<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
  • The velocity is the derivative of the position.
  • The acceleration is the derivative of the velocity.

In this problem, the position is:

s(t) = t^3 - 3t^2 + 8

item i:

Velocity is the <u>derivative of the position</u>, hence:

v(t) = 3t^2 - 6t

Item ii:

v(3) = 3(3)^2 - 6(3) = 27 - 18 = 9

The speed is of 9 m/s.

Item iii:

Derivative of the velocity, hence:

a(t) = 6t - 6

Item iv:

a(2) = 6(2) - 6 = 6

The acceleration is of 6 m/s².

Item v:

t for which a(t) = 0, hence:

6t - 6 = 0

6t = 6

t = \frac{6}{6}

t = 1

Hence 1 second.

You can learn more about derivatives at brainly.com/question/14800626

7 0
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