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iVinArrow [24]
4 years ago
8

Last week jean did two sit ups on monday and three sit ups on Wednesday. This week, jean did three times as many as last week. H

ow many sit ups did jean do this week?
Mathematics
2 answers:
IRINA_888 [86]4 years ago
8 0
2 on mon. plus 3 on wed. is 5. 3 x 5 is 

15 sit ups
BartSMP [9]4 years ago
4 0
If he did 2 on Monday and 3 on Wednesday he did 5 total. If he did 3 times that multiply 5 by 3 to get 15. So he did 15 sit-ups this week.
2+3=5 5*3=15
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Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
paul , Nadia and Jim have some stickers. Nadia has 3 times as many stickers as jim. Paul has 25 stickers more that Nadia. Paul a
alexandr402 [8]
Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85

85-25 = 60
(Subtract Nadia's and Paul's stickers all together with the stickers that Paul have more so both of the stickers are balance)

Nadia = 60/2 =30
Paul = 30+25 =55

Jim= 30/3=10

#Jim have 10 stickers


4 0
3 years ago
2. Write the equation of the circle in general form
Anon25 [30]
(-1,-2) and (-1,4)
so these have same x values, but different y values, so these are on differnt sidef of circle

distanc between them is 6
6/2=3
radius=3

so move 3 units up from (-1,-2)
(-1,1)
so

if center is (h,k) and radius is r then
(x-h)^2+(y-k)^2=r^2

(-1,1) is center and r=3

(x-(-1))^2+(y-1)^2=3^2
(x+1)^2+(y-1)^2=9
5 0
3 years ago
A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the
Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

6 0
3 years ago
Calculate s_75 for the arithmetic sequence defined by {a_n}={67-2n}
nalin [4]

Answer:

we go to the same school

Step-by-step explanation:

kik me at my name

3 0
3 years ago
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