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Veseljchak [2.6K]

3 years ago

7

What are data sorted into before they are plot as a histogram

1 answer:

Olin [163]3 years ago

8 0

Answer:

use google lol

use google lol

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Which of these situations can be represented with an integer that, when combined with the opposite of 8, makes 0?

Lerok [7]

-8
On the number line if you are at positive 8 and add -8 you will lose 8 and get zero! Hope this helps!

6 0

1 year ago

Express in exponential form.<br><br> x = logby

Lunna [17]

X = log (base b) y
The base of the log becomes the base of the exponent.
The x and y switch.
b^x = y

6 0

4 years ago

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Will mark brainliest!! Please answer ASAP

rusak2 [61]

Answer:

y=5

Step-by-step explanation:

y= 5 is always parallel to x axis

8 0

3 years ago

If $6500 is invested at a rate of 6% compounded continuously, find the balance in the account after 3 years

Alex787 [66]

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6500\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &3 \end{cases} \\\\\\ A=6500e^{0.06\cdot 3}\implies A=6500e^{0.18}\implies A\approx 7781.91$

6 0

3 years ago

Last year, Edward spent a total of $626.14 on his power bill. Rounding the total bill to the nearest tens place, approximate how

zlopas [31]

Answer:

He spent around $ 52.17 in each month.

Step-by-step explanation:

Last year the power bill price = $ 626.14 ≈ $ 626

We know that in a year 12 months. so power bill of each month in last year is calculated as follows

$Power \ bill \ of \ each \ month = \frac{Total \ bill \ of \ the \ year}{12}$

$Power \ bill \ of \ each \ month = \frac{626}{12}$

$Power \ bill \ of \ each \ month =$ $ 52.17

Therefore he spent around $ 52.17 in each month.

7 0

4 years ago