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anzhelika [568]
4 years ago
8

Help me with a. b. c. I need help

Mathematics
1 answer:
hammer [34]4 years ago
3 0

Answer:

a) Perimeter = 20.5 Inches

   Area is 15 Sq Inches

b) Perimeter is 61.4 Cms

    Area is 210 Sq cm

c) Perimeter is 22 yards

   Area is 21 Sq Yards

Step-by-step explanation:

a) Perimeter = sum of all the sides

= 8+7.5+5

=20.5

Perimeter = 20.5 Inches

Area of Triangle =\frac{1}{2} \times height \times Base

Base = 7.5 In

Height = 4 In

A = \frac{1}{2} \times 4 \times 7.5

A = 2 \times 7.5

A = 15

Hence Area is 15 Sq Inches

b)  Perimeter = Sum of all the sides

P=13+23+13.4+12

P=61.4

Perimeter is 61.4 Cms

Area of trapezium = \frac{1}{2} \times height  \times (sum \ of \ parallel \ sides)

A= \frac{1}{2} \times 12 \times (12+23)

A= 6 \times 25

A=210

Area is 210 Sq cm

c) Perimeter = Sum of all the sides

P = 7+4+7+4 ( as Opposite sides are equal in a parallelogram

P = 22

Perimeter is 22 yards

Area of a parallelogram = base \times height

A= 7 \times 3

A = 21

Area is 21 Sq Yards

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May I please receive help???? <br> Please
zheka24 [161]

Answer:

43°

Step-by-step explanation:

<h2><u>Equation:</u></h2>

<u />

m∠ABD = m∠1 + m∠2

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68° = m∠1 + (m∠1 + 18°)

<h2><u>Solve:</u></h2>

68° = m∠1 + (m∠1 + 18°)

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50° = 2(m∠1)

25 = m∠1

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Know that we know that m∠1 is, we can add 18* to find m∠2

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