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posledela
3 years ago
5

if you want to exclude a portion of an image which option should be chosen?? A. Arrange B. Position C. Crop D. Delete

Computers and Technology
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
It would be C- crop. This allows you to specifically delete parts of the image using drag and drop features. Hope this helps!
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Which of the following technologies is the best choice to convey urgent and highly sensitive information? telephone fax letter e
snow_lady [41]
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Using the Internet, search and discuss why naming conventions are important and why programmers should consistently follow them.
LiRa [457]

Answer:

Answered below

Explanation:

Some variable naming conventions include;

1) Variable should begin with either a letter or an underscore.

2) Variables having multiple words should have the first letter of every word after the first word, capitalized. This is the camelCase style.

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7 0
3 years ago
Display the cost of landscaping a backyard with sod that is sold by the square foot and fencing that is sold by the foot. The in
Ipatiy [6.2K]

Answer:

length = float(input("Enter length of the backyard in foot: "))

width = float(input("Enter width of the backyard in foot: "))

sod_price = float(input("Enter the price of sod per square foot: "))

fencing_price = float(input("Enter the price of fencing per foot: "))

area = length * width

perimeter = 2 * (length + width)

cost = sod_price * area + fencing_price * perimeter

print("The cost of landscaping is $" + str(cost))

Explanation:

*The code is in Python.

Ask the user to enter the length, width, sod_price, and fencing_price

Calculate the area and perimeter of the backyard

Calculate the cost, sod_price * area + fencing_price * perimeter

Print the cost

7 0
3 years ago
Assume that two parallel arrays have been declared and initialized: healthOption an array of type char that contains letter code
eduard

/*

Since we have to check the first two options only as mentioned in last part of question the loop will work 2 times only and will compare the cost of first element and second and assign the healthoption accordingly

*/

for(int i =0;i<=1;i++){

if(annualCost[i]<annualCost[i+1]

best2 = healthOption[i]

else

best2 = healthOption[i+1]

}

6 0
3 years ago
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