I think it would be 1 week.
Answer:
Q' = (6,3)
Step-by-step explanation:
You can think of this problem in two ways:
Graph:
I've shown my working for this, where I've counted how many units it takes to get from point Q to the axis through which im reflecting. There are 6 units between Q and the y axis, so naturally there should be 6 units between Q' and the y axis.
Coordinates:
Since this is a reflection through an axis, we can assume that the the x coordinate of point Q' will be equal and opposite to Q. Therefore, while the x coordinate of Q was -6, of Q' it's 6
Answer:
12units²
Step-by-step explanation:
Given a triangle that has sides that measure 2 units, 5 units, and 5.39 units,
Perimeter of the triangle = 2 + 5 + 5.39
Perimeter of the triangle = 12.39units
since the circumference is equal to the perimeter of the triangle, hence;
C = 12.39units
C = 2πr
r is the radius of the circle
12.39 = 2(3.14)r
12.39 = 6.28r
r = 12.39/6.28
r = 1.973 units
Get the area
Area = πr²
Area of the circle = 3.14(1.973 )²
Area of the circle = 3.14(3.892)
Area of the circle = 12.22units²
Area of the circle ≈ 12units²
The answer is going to be 20x-4