The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.
So, for a quadratic equation ax + bx + c = 0, the roots are
With a = 9, b = -6 and c = 5, the roots of our equation are
Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.
So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots
Learn more about quadratic equations here:
brainly.com/question/18117039
Answer: look at the ss :)
Step-by-step explanation:
The answer is <span>20.3896551724</span>
320×.15= 48
320-48=$272
320-45=$275
so the 15% off is the better deal
Answer:
(4, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equation using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
2x - 3y = 5
4x + 2y = 18
<u>Step 2: Rewrite systems</u>
2x - 3y = 5
y = 9 - 2x
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute: 2x - 3(9 - 2x) = 5
- Distribute -3: 2x - 27 + 6x = 5
- Combine like terms: 8x - 27 = 5
- Add 27 on both sides: 8x = 32
- Divide 8 on both sides: x = 4
<u>Step 4: Solve for </u><em><u>y</u></em>
- Define: 2x - 3y = 5
- Substitute: 2(4) - 3y = 5
- Multiply: 8 - 3y = 5
- Isolate <em>y</em> term: -3y = -3
- Isolate <em>y</em>: y = 1
And we have our final answer!
