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3 years ago

Steve's mom's age is 7 years less than 3 times Steve's ages.

Mathematics

2 answers:

Elden [556K]3 years ago

4 0

Answer:

Steve's mom is 65.

Step-by-step explanation:

Let s = Steve's age.

s + (3s - 7) = 65

4s - 7 = 65

4s = 72

s = 18

Check:

Steve is 18

His mom is (3 * 18) - 7 = 54 - 7 = 47

14 + 47 = 65

Yep.

18 + 47 = 65

murzikaleks [220]3 years ago

3 0

Answer:

y = 3x + 7

(Not sure what the question was so, I just put it in slope intercept form)

Step-by-step explanation:

Let x be Steve's age.

Steve = x

Steve's Mom = y

Now let's create an equation:

y - 7 = 3x

y = 3x + 7

(Not sure what the question was so, I just put it in slope intercept form)

Please let me know if I misunderstood the question that way I can help you! <3

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Find the volume of the solid generated when R (shaded region) is revolved about the given line. x=6−3sec y, x=6, y= π 3, and

Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$

where:

$r=6-(6-3 sec(y))$

$r=3 sec(y)$

a=0

$b=\frac{\pi}{3}$

so the volume becomes:

$V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy$

This can be simplified to:

$V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy$

and the integral can be rewritten like this:

$V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy$

which is a standard integral so we solve it to:

$V=9\pi[tan y]\limits^\frac{\pi}{3}_0$

so we get:

$V=9\pi[tan \frac{\pi}{3} - tan 0]$

which yields:

$V=9\pi\sqrt{3}$ ]

6 0

4 years ago

10.25 feet long, 8 feet wide, and 4 feet high. what volume of compacted trash will the dumpster hold

agasfer [191]

Answer:

The volume of compacted trash is 328 ft³ .

Step-by-step explanation:

Given as :

The length of compacted trash = 10.25 feet

The width of the compacted trash = 8 feet

The height of the compacted trash = 4 feet

Let The volume of the trash = V ft³

The volume of compacted trash is given as the product of length width and height

So, V = length × width × height

or, V = 10.25 × 8 × 4 ft³

or, V = 328 ft³

Hence The volume of compacted trash is 328 ft³ . Answer

5 0

3 years ago

A friend has a 83% average before the final exam for a course. That score includes everything but the final, which counts for 25

Klio2033 [76]

Answer:

$\mathrm{Best\:course\:grade\:possible:\:}87.25\%,\\\mathrm{Minimum\:score\:on\:final\:to\:earn\:at\:least\:a\:75\%\:for\:the\:course:\:}51\%$

Step-by-step explanation:

Assuming the maximum score for the final is $100\%$ , we can multiply each score by its respective course weight and add them together to give a final score. If your friend did receive this maximum score of $100\%$ , their overall grade for the course would be: