The Figures shown are similar. What is the scale factor?

Printing machine A and printing machine B print the same newspaper printout, but machine B prints at half the rate of machine A.

klemol [59]

Answer:

The answer is below

Step-by-step explanation:

Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:

y = (1/2)x (1)

Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:

200/x + 200/y = 4 (2)

Put y = (1/2)x in equation:

$\frac{200}{x}+\frac{200}{(\frac{1}{2} )x}=4\\ \\ \frac{200}{x}+\frac{400}{x}=4\\\\Multiply\ through\ by\ x:\\\\200+400=4x\\\\4x=600\\\\x=150$

Put x = 150 in equation y:

y=(1/2)150 = 75

Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour

6 0

4 years ago

Farmer Ed has 8,000 meters of fencing & wants to enclose a rectangular plot that borders a river. If farmer Ed does not fenc

attashe74 [19]

Answer:

largest area that can be enclosed = 8,000,000 m²

Step-by-step explanation:

Since it is a rectangle plot, the area is expressed as; A = xy, where x is length and y is width.

Because it is next to the river, he only needs to fence three sides, so amount of fencing; F = x + 2y.

Since we know the amount of fencing available is 8000m, we get:

8000 = x + 2y

solving for x, we have;

x = 8000 - 2y

substitute 8000 - 2y for x into the area equation to give;

A = (8000 - 2y)y distribute

A = -2y² + 8000y

Now, due to the negative sign next to 2, this will be a parabola which opens down, meaning that the point of maximum area will be at the vertex,

Thus; y = -b/2a = -8000/[2(-2)] = 2000

x = 8000 - 2(2000) = 4000

A = 4000(2000) = 8,000,000 m²

8 0

4 years ago

Max is on a diet.he want to have a snack.he cam have a snack if it less than 220kcal

Ludmilka [50]

500/20 = 25kcal per piece
8 * 25 = 200kcal.....yes, he is able to have 8 pieces

4 0

4 years ago

Assume the population has a distribution with a mean of 110 and a standard deviation of 8. For a random sample of size 40, find

VARVARA [1.3K]

Answer:

109.33

Step-by-step explanation:

given that the population has a distribution with a mean of 110 and a standard deviation of 8

Sample size n = 40

Std error of sample mean = std dev/square root of sample size

= $\frac{8}{\sqrt{40} } \\=1.265$

From std normal distribution table we find that 30th percentile for Z is

-0.5244

Corresponding x score = $110-0.5244*1.265=109.33663$

30th percentile = 109.33663

=109.33

8 0

4 years ago

PLEASE HELP ME! IT WOULD BE VERY MUCH APPRECIATED!

shusha [124]

Answer:

A

Step-by-step explanation:

common ratio of 0.5.

hmu for more

7 0

4 years ago