Answer:
(a) P(A1 ∪ A2) = 0.35
Step-by-step explanation:
(a) A1 ∪ A2 :
We start by defining the events.
A1 : '' awarded project 1''
A2 : ''awarded project 2''
A3: ''awarded project 3''
In set theory we write the union of events A and B as A∪B.
A∪B means that the event A occurs,event B occurs or either both events occurs at the same time.
The probability is given by the equation :
P(A∪B) = P(A) + P(B) - P(A∩B) (1)
Where the event (A∩B) is the event where A and B occur at the same time
and P(A∩B) is the probability of (A∩B)
Using the equation (1) :
P(A1 ∪ A2) = P(A1) + P(A2) - P(A1∩A2)
P(A1 ∪ A2) = 0.22 + 0.25 - 0.12
P(A1 ∪ A2) = 0.35
1.2 is less than 1.5
If you cancel out 1 from both numbers you're left with .2 and .5
Multiply both by 10 and get 2 and 5.
Obviously 2 is less than 5.
According to given expression, we can say that the Triangles HZC and PEF are congruent, Therefore their corresponding sides will be equal.
that is :
and value of CH = 20 units
So, FP = CH = 20 units
hence, value of FP <u>can be </u><u>determined</u> .
Answer:
106
Step-by-step explanation:
Ok this question is a bit confusing but once you understand the concept you will be able to answer the question correctly
Always know that bracket is solved first once it is found in the question
So back to the question
-4(2-5)2+82
So let's get to work...
Bracket first
-4(-3)2+82
Multiply with the number at the front then followed by the one at the back
(+12)2+82
24+82
106
Therefore the final answer is 106
I believe you understand how we get the answer...just be careful when solving this kind of question... simple
