Answer:
A. Lookup
Explanation:
You would use the Lookup field to store a value from another table.
Answer:
The answer for this question is b Add to
Answer:
Slide selection
Title slide
Content wise slides
Little short animations
Conclusion slide
Thank you slide
Dont forget to use Times New Roman font as using this font makes people easier to understand the concept.
Give attractive headings
Give 2 minutes per each slide for explanation
Make this presentation very good with confidence and don't forget to include tactful facts
Dont get a panic attack Haha
Answer:
Answer is provided in the explanation section
Explanation:
Given data:
Bandwidth of link = 10* 106 bps
Length of packet = 12* 103 bits
Distance of link = 40 * 103m
Transmission Speed = 3 * 108 meters per second
Formulas:
Transmission Delay = data size / bandwidth = (L /B) second
Propagation Delay = distance/transmission speed = d/s
Solution:
Transmission Delay = (12* 103 bits) / (10* 106 bps) = 0.0012 s = 1.2 millisecond
Propagation Delay = (40 * 103 meters)/ (3 * 108mps) = 0.000133 = 0.13 millisecond
Answer:
In computer science, scalability is the ability of an application or product that could be software or software to continue responding well when its context is increased in volume or size to meet the user demand. Typically, when a product becomes aging or the context demands a rescaling to a larger size or volume, if the product is prepared to respond to this demand, then it's called a scalable product.
