Answer:

Step-by-step explanation:
![0 = {x}^{2} + 24 \\ \\ -24 = {x}^{2} \\ \\ \sqrt{[4][6][i]} = \sqrt{{x}^{2}} \\ \\ ±2i\sqrt{6} = x](https://tex.z-dn.net/?f=0%20%3D%20%7Bx%7D%5E%7B2%7D%20%2B%2024%20%5C%5C%20%5C%5C%20-24%20%3D%20%7Bx%7D%5E%7B2%7D%20%5C%5C%20%5C%5C%20%5Csqrt%7B%5B4%5D%5B6%5D%5Bi%5D%7D%20%3D%20%5Csqrt%7B%7Bx%7D%5E%7B2%7D%7D%20%5C%5C%20%5C%5C%20%C2%B12i%5Csqrt%7B6%7D%20%3D%20x)
The square root of something is ALWAYS negative and positive.
I am joyous to assist you anytime.
Answer:
339.2925
Step-by-step explanation:
Answer:
9<n<17.
Step-by-step explanation:
Answer:
Bigger number = 42
Smaller number = 10
Step-by-step explanation:
Step 1: Define variables
<em>x</em> = larger number
<em>y</em> = smaller number
Step 2: Write systems of equations
x + 2y = 62
3x = y + 116
Step 3: Rewrite 1st equation
x = 62 - 2y
Step 4: Substitution
3(62 - 2y) = y + 116
186 - 6y = y + 116
186 = 7y + 116
70 = 7y
y = 10
Step 5: Plug in <em>y</em> to find <em>x</em>
x + 2(10) = 62
x + 20 = 62
x = 42