The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
han the width, x, which interval can be the possible widths?
1 answer:
X(x+18) <= 175
<span>x^2+18x-175 <= 0 </span>
<span>(x+25)(x-7) <= 0 </span>
<span>So, -25 <= x <= 7 </span>
<span>Or, for real-world tables, </span>
You might be interested in
Answer:
is a lot of them
Step-by-step explanation:
94+1, 95+0, 79+16
E=16 pls brainliest me have a good day/night
62 is the awnser for this
Volume of a cube = 1/3 volume of cube = 1/3 * 36 = 12 cubic feet.
