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nlexa [21]
3 years ago
5

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

han the width, x, which interval can be the possible widths?
Mathematics
1 answer:
Margarita [4]3 years ago
6 0
X(x+18) <= 175 
<span>x^2+18x-175 <= 0 </span>
<span>(x+25)(x-7) <= 0 </span>
<span>So, -25 <= x <= 7 </span>
<span>Or, for real-world tables, </span>
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Answer:

The solution to the system is the pair (9, 6)

Step-by-step explanation:

Hi!

First, let´s write the system of equations:

-y² + 6y + x -9 = 0

6y = x +27

The solutions of the system are the pairs (x, y) that satisfy both equations.

Let´s take the second equation and solve it for x:

6y = x +27

Subtract 27 from both sides of the equation

6y - 27 = x

Now, we can replace x in the first equation and solve it for y:

-y² + 6y + x -9 = 0

-y² + 6y + 6y - 27 -9 = 0

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Notice that -y² + 12y - 36 = -(y - 6)², then:

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(alternatively you can solve the quadratic equation using the quadratic formula).

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x = 6y -27

x = 6·6 -27

x = 9

The solution to the system is the pair (9, 6)

Please see the attached figure. The point where the curves intersect is the solution to the system.

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