The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
han the width, x, which interval can be the possible widths?
1 answer:
X(x+18) <= 175
<span>x^2+18x-175 <= 0 </span>
<span>(x+25)(x-7) <= 0 </span>
<span>So, -25 <= x <= 7 </span>
<span>Or, for real-world tables, </span>
You might be interested in
2/9(x)9/4 =18/36
1/2
2/9(x)-9
-18/9
-2
Answer:: y=1/2x-2
There both being multiplied by 5
Answer:
I think t is 10, not completely sure though
Step-by-step explanation:
7-10/8-9= -3/-1 =3
I don't know, I just need points
lol
Answer:
850000
Step-by-step explanation:
0\/4,round down.
5/\9,round up
