Given:
The expression is
To find:
The product of prime polynomials which is equivalent to the given expression.
Solution:
We have,
Taking out the common factors, we get
It can be written as
![[\because a^3-b^3=(a-b)(a^2+ab+b^2)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E3-b%5E3%3D%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29%5D)
Therefore, the correct option is B.
A) Probability that at least one of these golfers makes a hole in one on the 10th hole at the same tournament is
<span>=1−(<span>2493/2494</span><span>)^<span>5
=1-(0.99)^5
= 1- 0.96
=0.4
b) T</span></span></span><span>he probability that all of these golfers make a hole-in-one on the 10th hole at the same tournament
=</span>(<span>1/2494</span><span>)<span>5
</span></span>
which is nearly zero.
Answer:
-7
Step-by-step explanation:
-9q = 63
q= 63/-9 = -7
The correct answer is Choice C.
The ratio given is 2 to 3. All of the choices give the total of 15 glass as needed. However, only choice C is also in the ratio of 2 to 3.
6/9 can be reduced to the fraction 2/3 by dividing by 3.
Solve each of the equations independently, then determine if the are continuous or discontinuous.
15≥-3x [start here]
-5≤x [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5 [just turned around for analysis]
Next equation:
2/3x≥-2 [start here]
x≥-2(3/2) [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3
So, (according to the first equation) all values of x must be greater than, or equal to -5.
(According to the second equation) all values of x must be greater than, or equal to -3.
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.
