Answer:
58.03
Step-by-step explanation:
What I did first to make it easier was make 5.5 to .055 and when you multiply those two together you get 3.025 which if you round it up becomes 3.03 and when you add 55 you get 58.03
Answer:
Step-by-step explanation:
( x , y ) ----> ( x - 1 , y ) ------> ( 2(x-1) , 2y ) = <em>( 2x - 2 , 2y )</em>
Showin that x=p the. The only way that y=q is because the others are the same say x=179 the y has to =1 and then p=179 so q has to equal =1
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
It's table D
Step-by-step explanation:
I just took the test.