Answer:
int main() {
int _2dArray[32][32];
for (int i = 0; i < 32; i++) {
for (int j = 0; j < 32; j++) {
_2dArray[i][j] = j + i * 32;
}
}
return 0;
}
Explanation:
Here is a generic C/C++ 2d array traversal and main function example. The rest you'll have to figure out based on what kind of app you're making.
Good luck!
Answer:
x^2 * b^2
Explanation:
Like 3 squared times 2 squared is 3*3*2*2. Similarly the expression given in the question is equal to x*x*b*b. And that explains what is mentioned in question.
Answer:
Follows are the method definition to this question:
void printArray(int arrayToPrint[], int arraySize) //defining a method printArray that accepts two array in its parameters
{
for (int j = 0; j < arraySize; j++)//defining for loop print Serial numbers
{
Serial.print("[");//use print method to print square bracket
Serial.print(j);//use print method to print Serial numbers
Serial.print("]: ");//use print method to print square bracket
Serial.println(arrayToPrint[j]);//printing array value
}
}
Explanation:
In the above code, a method "printArray" is declared that holds two arrays "arrayToPrint and arraySize" as a parameter, and inside the method is used for loop to print the values.
In the loop, first, it uses the square bracket to print the serial number and in the last step, it prints array values.
